题面据 IMO Shortlist 可核档案整理;中文题意为本站自译,公式请以原始来源为准。
A crazy physicist discovered a new kind of particle which he called an imon, after some of them mysteriously appeared in his lab. Some pairs of imons in the lab can be entangled, and each imon can participate in many entanglement relations. The physicist has found a way to perform the following two kinds of operations with these particles, one operation at a time. (i) If some imon is entangled with an odd number of other imons in the lab, then the physicist can destroy it. (ii) At any moment, he may double the whole family of imons in his lab by creating a copy of each imon . During this procedure, the two copies and become entangled if and only if the original imons and are entangled, and each copy becomes entangled with its original imon ; no other entanglements occur or disappear at this moment. Prove that the physicist may apply a sequence of such operations resulting in a family of imons, no two of which are entangled. (Japan)
一位疯狂的物理学家发现了一种新的粒子,他将其称为“离子”,其中一些粒子神秘地出现在他的实验室中。实验室中的一些离子对可以纠缠,并且每个离子可以参与许多纠缠关系。物理学家找到了一种用这些粒子执行以下两种操作的方法,一次一种操作。 (i) 如果一些离子在实验室中与奇数个其他离子纠缠在一起,那么物理学家就可以摧毁它。 (ii) 在任何时候,他都可以通过创建每个 imon 的副本 将其实验室中的整个 imon 家族加倍。在此过程中,两个副本 和 变得纠缠当且仅当原始 imon 和 纠缠时,并且每个副本 与其原始 imon 纠缠;此刻没有其他纠缠发生或消失。证明物理学家可以应用一系列这样的操作来产生一个伊蒙族,其中没有两个是纠缠的。 (日本)
提示 1
先决定对象是什么:集合、图、排列、颜色、路径,还是一次操作后的状态。
提示 2
找一个极端对象、双计数式、不变量,或把限制转成图上的局部条件。
提示 3
把局部限制累加成全局矛盾,或给出覆盖全部情形的构造。
完整解答
这页先给题面、题型和提示阶梯,完整证明留给读者逐步展开。2013 年 IMO Shortlist C3 可先归入组合:第一步把题设翻成对象、条件、目标三行;第二步沿提示寻找不变量、标准构型或关键变形;第三步补齐边界情形,并回到题目原要求核对。
这题适合先独立想一轮再打开提示。不要急着搜索完整解答,先问自己:题面里最硬的限制是哪一句?