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数学 / 几何原本 / Proposition I.14

第1卷命题 14 · 相邻角合二直角则两线成一直线

If with any straight line, and at a point on it, two straight lines not lying on the same side make the adjacent angles equal to two right angles, the two straight lines will be in a straight line with one another.

若两条直线从同一点出发,并与另一条直线形成相邻两角且合为两个直角,则这两条直线成一直线。

A B C D E
fig-1

AB 立在 B 点;BC 向左、BD 向右两边相邻角合为二直角;BE(虚设)与 BC 成一直线,但与 BD 不同,导出矛盾。

线

正文图形由校订坐标生成;点、线、角、圆可与证明和问答联动。

分步证明Step-by-step proof
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  1. For with any straight line AB, and at the point B on it, let the two straight lines BC, BD not lying on the same side make the adjacent angles ABC, ABD equal to two right angles; I say that BD is in a straight line with CB. For, if BD is not in a straight line with BC, let BE be in a straight line with CB. Then, since the straight line AB stands on the straight line CBE, the angles ABC, ABE are equal to two right angles.

    设两条线从同一点在同侧与另一线形成相邻角,且合为两个直角。

  2. [I. 13] But the angles ABC, ABD are also equal to two right angles; therefore the angles CBA, ABE are equal to the angles CBA, ABD. [Post. 4 and C.N. 1] Let the angle CBA be subtracted from each; therefore the remaining angle ABE is equal to the remaining angle ABD, [C.N. 3] the less to the greater: which is impossible.

    若这两条线不成一直线,则还存在真正的直线方向与其中一条相邻。

  3. Therefore BE is not in a straight line with CB. Similarly we can prove that neither is any other straight line except BD.

    euclid-elements/book1-prop-013,这条真正直线形成的相邻角也合为两个直角。

  4. Therefore CB is in a straight line with BD. Therefore etc.

    从相等总量中减去公共角,推出两条不同线重合,矛盾;故两线成一直线。