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数学 / 几何原本 / Proposition VII.35

第7卷命题 35 · 两数公倍数整除性质

If two numbers measure any number, the least number measured by them will also measure the same.

如果两个数都量尽某个数,那么它们所量尽的最小数也能量尽该数。

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分步证明Step-by-step proof
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  1. For let the two numbers A, B measure any number CD, and let E be the least that they measure; I say that E also measures CD.

    设两数A、B量尽某数CD,且E是它们量尽的最小数。

  2. For, if E does not measure CD, let E, measuring DF, leave CF less than itself.

    假设E不量尽CD,则让E量尽DF,余下CF小于E。

  3. Now, since A, B measure E, and E measures DF, therefore A, B will also measure DF.

    由于A、B量尽E,且E量尽DF,所以A、B也量尽DF。

  4. But they also measure the whole CD; therefore they will also measure the remainder CF which is less than E: which is impossible.

    但A、B也量尽整个CD,因此它们也量尽余数CF,而CF小于E,这是不可能的。