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数学 / 几何原本 / Proposition V.22

第5卷命题 22 · 比例传递定理

elem.5.22

若有任意多个量,以及与其个数相等的另一些量,它们两两成相同比例,则它们也成相同比例(经等距传递)。

A B C D E F G H K L M N
fig-1

若任意多个量成同比例传递(A:B = D:E, B:C = E:F),则首尾也成同比例:A:C = D:F。G、H、K、L、M、N 为对应等倍量。

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分步证明Step-by-step proof
1 / 4
  1. Let there be any number of magnitudes A, B, C, and others D, E, F equal to them in multitude, which taken two and two together are in the same ratio, so that, as A is to B, so is D to E, and, as B is to C, so is E to F; I say that they will also be in the same ratio ex aequali, <that is, as A is to C, so is D to F>. For of A, D let equimultiples G, H be taken, and of B, E other, chance, equimultiples K, L; and, further, of C, F other, chance, equimultiples M, N.

    设量A、B、C与量D、E、F个数相等,且A:B=D:E,B:C=E:F。

  2. Then, since, as A is to B, so is D to E, and of A, D equimultiples G, H have been taken, and of B, E other, chance, equimultiples K, L, therefore, as G is to K, so is H to L. [V. 4] For the same reason also, as K is to M, so is L to N.

    取A、D的等倍数G、H,B、E的任意等倍数K、L,C、F的任意等倍数M、N。

  3. Since, then, there are three magnitudes G, K, M, and others H, L, N equal to them in multitude, which taken two and two together are in the same ratio, therefore, ex aequali, if G is in excess of M, H is also in excess of N; if equal, equal; and if less, less. [V. 20] And G, H are equimultiples of A, D, and M, N other, chance, equimultiples of C, F.

    由A:B=D:E得G:K=H:L;同理K:M=L:N。

  4. Therefore, as A is to C, so is D to F.

    由V.20,若G>M则H>N,若G=M则H=N,若G<M则H<N;故由V.定义5得A:C=D:F。