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数学 / 几何原本 / Proposition X.11

第10卷命题 11 · 比例与可公度性传递

If four magnitudes be proportional, and the first be commensurable with the second, the third will also be commensurable with the fourth; and, if the first be incommensurable with the second, the third will also be incommensurable with the fourth.

若四个量成比例,且第一个与第二个可公度,则第三个与第四个也可公度;若第一个与第二个不可公度,则第三个与第四个也不可公度。

A B C D
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分步证明Step-by-step proof
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  1. Let A, B, C, D be four magnitudes in proportion, so that, as A is to B, so is C to D, and let A be commensurable with B; I say that C will also be commensurable with D. For, since A is commensurable with B, therefore A has to B the ratio which a number has to a number.

    设A、B、C、D四个量成比例,即A比B等于C比D,且A与B可公度。

  2. [X. 5] And, as A is to B, so is C to D; therefore C also has to D the ratio which a number has to a number; therefore C is commensurable with D.

    因A与B可公度,故A与B的比等于某两数之比(X.5)。

  3. [X. 6] Next, let A be incommensurable with B; I say that C will also be incommensurable with D. For, since A is incommensurable with B, therefore A has not to B the ratio which a number has to a number.

    由比例关系,C与D的比也等于该两数之比,故C与D可公度(X.6)。

  4. [X. 7] And, as A is to B, so is C to D; therefore neither has C to D the ratio which a number has to a number; therefore C is incommensurable with D.

    若A与B不可公度,则A与B的比不等于任何两数之比(X.7),从而C与D的比也不等于任何两数之比,故C与D不可公度(X.8)。