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数学 / 几何原本 / Proposition V.14

第5卷命题 14 · 比例大小传递定理

elem.5.14

若第一量比第二量等于第三量比第四量,且第一量大于第三量,则第二量也大于第四量;若相等则相等;若小于则小于。

A B C D
fig-1

A:B = C:D,且 A > C;由比例性质推出 B > D。两列分别置 A、B(左)与 C、D(右)。

线

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分步证明Step-by-step proof
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  1. For let a first magnitude A have the same ratio to a second B as a third C has to a fourth D; and let A be greater than C; I say that B is also greater than D. For, since A is greater than C, and B is another, chance, magnitude, therefore A has to B a greater ratio than C has to B.

    设第一量A比第二量B等于第三量C比第四量D,且A大于C。

  2. [V. 8] But, as A is to B, so is C to D; therefore C has also to D a greater ratio than C has to B.

    因A大于C,且B为任意量,故A比B的比大于C比B的比(V.8)。

  3. [V. 13] But that to which the same has a greater ratio is less; [V. 10] therefore D is less than B; so that B is greater than D.

    但A比B等于C比D,故C比D的比也大于C比B的比(V.13)。

  4. Similarly we can prove that, if A be equal to C, B will also be equal to D; and, if A be less than C, B will also be less than D.

    同一量对之具有更大比的量较小(V.10),故D小于B,即B大于D。同理可证相等和小于的情形。