灯下 登录
数学 / 几何原本 / Proposition VIII.5

第8卷命题 5 · 平面数之比由边之比复合

Plane numbers have to one another the ratio compounded of the ratios of their sides.

两个平面数之比等于它们边长之比复合而成的比。

A A_r B B_r C C_r D D_r E E_r F F_r G G_r H H_r K K_r L L_r
fig-1

本页以“平面数之比由边之比复合”整体图解辅助阅读;点、线、角、圆索引已按命题文字和证明步骤校订,可与证明和问答联动。

线

正文图形由校订坐标生成;点、线、角、圆可与证明和问答联动。

分步证明Step-by-step proof
1 / 4
  1. Let A, B be plane numbers, and let the numbers C, D be the sides of A, and E, F of B; I say that A has to B the ratio compounded of the ratios of the sides. For, the ratios being given which C has to E and D to F, let the least numbers G, H, K that are continuously in the ratios C : E, D : F be taken, so that, as C is to E, so is G to H, and, as D is to F, so is H to K.

    设A、B为平面数,C、D为A的边,E、F为B的边。取连续成比例C:E和D:F的最小三个数G、H、K,使得C:E=G:H且D:F=H:K。

  2. [VIII. 4] And let D by multiplying E make L. Now, since D by multiplying C has made A, and by multiplying E has made L, therefore, as C is to E, so is A to L.

    令D乘以E得L。由于D乘以C得A,乘以E得L,故C:E=A:L。又C:E=G:H,所以G:H=A:L。

  3. [VII. 17] But, as C is to E, so is G to H; therefore also, as G is to H, so is A to L. Again, since E by multiplying D has made L, and further by multiplying F has made B, therefore, as D is to F, so is L to B.

    由于E乘以D得L,乘以F得B,故D:F=L:B。又D:F=H:K,所以H:K=L:B。

  4. [VII. 17] But, as D is to F, so is H to K; therefore also, as H is to K, so is L to B. But it was also proved that, as G is to H, so is A to L; therefore, ex aequali, as G is to K, so is A to B.

    已证G:H=A:L,由等比定理得G:K=A:B。因此A与B的比等于由C:E和D:F复合而成的比。