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数学 / 几何原本 / Proposition IX.16

第9卷命题 16 · 互质数之比不可循环

If two numbers be prime to one another, the second will not be to any other number as the first is to the second.

若两数互质,则第二数不能与任何其他数成第一数比第二数之比例。

A A B B C C
fig-1

两数 A、B 互质;假设存在 C 使 A:B = B:C,由互素+最小数性质推 A 量 B,矛盾。

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分步证明Step-by-step proof
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  1. For let the two numbers A, B be prime to one another; I say that B is not to any other number as A is to B.

    设两数A、B互质,假设存在数C使得A比B等于B比C。

  2. For, if possible, as A is to B, so let B be to C.

    因A、B互质,故它们是最小的具有该比例的数(第七卷命题21)。

  3. Now A, B are prime, primes are also least, [VII. 21] and the least numbers measure those which have the same ratio the same number of times, the antecedent the antecedent and the consequent the consequent; [VII. 20] therefore A measures B as antecedent antecedent.

    最小数能量尽与其有相同比例的数相同次数,前项量尽前项,后项量尽后项(第七卷命题20)。

  4. But it also measures itself; therefore A measures A, B which are prime to one another: which is absurd.

    因此A量尽B(作为前项量尽前项),但A也量尽自身,故A量尽互质的A、B,矛盾。