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数学 / 几何原本 / Proposition I.18

第1卷命题 18 · 大边对大角

In any triangle the greater side subtends the greater angle.

任一三角形中,较大的边所对的角也较大。

A B C D
fig-1

三角形 ABC,AC>AB。在 AC 上取 AD=AB;连 BD,把不等关系传递到角。

线

正文图形由校订坐标生成;点、线、角、圆可与证明和问答联动。

分步证明Step-by-step proof
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  1. For let ABC be a triangle having the side AC greater than AB; I say that the angle ABC is also greater than the angle BCA. For, since AC is greater than AB, let AD be made equal to AB [I. 3], and let BD bejoined.

    设 AB 大于 AC。从 AB 上截取 AD 等于 AC(euclid-elements/book1-prop-003)。

  2. Then, since the angle ADB is an exterior angle of the triangle BCD, it is greater than the interior and opposite angle DCB.

    连接 CD,则三角形 ACD 是等腰三角形,相关底角相等。

  3. [I. 16] But the angle ADB is equal to the angle ABD, since the side AB is equal to AD; therefore the angle ABD is also greater than the angle ACB; therefore the angle ABC is much greater than the angle ACB.

    再用 euclid-elements/book1-prop-016 比较外角与内角。

  4. Therefore etc.

    得到较大边 AB 所对的角 ACB 大于较小边 AC 所对的角 ABC。