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数学 / 几何原本 / Proposition V.19

第5卷命题 19 · 比例转换定理

elem.5.19

若整体AB比整体CD等于减去的部分AE比减去的部分CF,则剩余部分EB比剩余部分FD也等于整体AB比整体CD。

A B C D E F I M O P R S
fig-1

若 AB:CD = AE:CF,则其差 EB:FD = AB:CD。下排 I、M、O、P、R、S 是引理里的辅助等倍量标号。

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分步证明Step-by-step proof
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  1. For since, as AB is to CD, so is AE to CF, alternately also, as BA is to AE, so is DC to CF. [V. 16] And, since the magnitudes are proportional componendo, they will also be proportional separando, [V. 17] that is, as BE is to EA, so is DF to CF, and, alternately, as BE is to DF, so is EA to FC.

    设AB:CD = AE:CF,由V.16交替得BA:AE = DC:CF。

  2. [V. 16] But, as AE is to CF, so by hypothesis is the whole AB to the whole CD. Therefore also the remainder EB will be to the remainder FD as the whole AB is to the whole CD.

    因合比成立,由V.17分比得BE:EA = DF:CF。

  3. [V. 11] Therefore etc. [ PORISM.

    再由V.16交替得BE:DF = EA:FC。

  4. From this it is manifest that, if magnitudes be proportional componendo, they will also be proportional convertendo.

    由假设AE:CF = AB:CD,故由V.11得EB:FD = AB:CD。