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数学 / 几何原本 / Proposition I.43

第1卷命题 43 · 平行四边形对角线旁的补形相等

In any parallelogram the complements of the parallelograms about the diameter are equal to one another.

在平行四边形中,沿对角线所成的两个补形彼此相等。

A B C D E F G H K
fig-1

平行四边形 ABCD,对角线 AC 上取点 K;过 K 作两组平行线 EH 与 FG 分割成四个小平行四边形。两个“补形” BK 和 KD 面积相等。

线

正文图形由校订坐标生成;点、线、角、圆可与证明和问答联动。

分步证明Step-by-step proof
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  1. Let ABCD be a parallelogram, and AC its diameter; and about AC let EH, FG be parallelograms, and BK, KD the so-called complements; I say that the complement BK is equal to the complement KD. For, since ABCD is a parallelogram, and AC its diameter, the triangle ABC is equal to the triangle ACD.

    在平行四边形内作对角线,并围出两个补形。

  2. [I. 34] Again, since EH is a parallelogram, and AK is its diameter, the triangle AEK is equal to the triangle AHK. For the same reason the triangle KFC is also equal to KGC.

    对角线两侧的大三角形相等(euclid-elements/book1-prop-034)。

  3. Now, since the triangle AEK is equal to the triangle AHK, and KFC to KGC, the triangle AEK together with KGC is equal to the triangle AHK together with KFC. [C.N. 2] And the whole triangle ABC is also equal to the whole ADC; therefore the complement BK which remains is equal to the complement KD which remains.

    这些大三角形分别由同一类小三角形和一个补形组成。

  4. [C.N. 3] Therefore etc.

    从相等整体中减去相等小三角形,余下补形相等。