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数学 / 几何原本 / Proposition III.18

第3卷命题 18 · 切线与半径垂直定理

elem.3.18

若一直线与圆相切,且从圆心到切点连一直线,则该连线垂直于切线。

A B C D E F G
fig-1

本页以“切线与半径垂直定理”整体图解辅助阅读;点、线、角、圆索引已按命题文字和证明步骤校订,可与证明和问答联动。

线

正文图形由校订坐标生成;点、线、角、圆可与证明和问答联动。

分步证明Step-by-step proof
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  1. For let a straight line DE touch the circle ABC at the point C, let the centre F of the circle ABC be taken, and let FC be joined from F to C; I say that FC is perpendicular to DE. For, if not, let FG be drawn from F perpendicular to DE.

    设直线DE切圆ABC于点C,取圆心F,连接FC。

  2. Then, since the angle FGC is right, the angle FCG is acute; [I. 17] and the greater angle is subtended by the greater side; [I. 19] therefore FC is greater than FG.

    假设FC不垂直于DE,则从F作FG垂直于DE。

  3. But FC is equal to FB; therefore FB is also greater than FG, the less than the greater: which is impossible. Therefore FG is not perpendicular to DE.

    由于角FGC为直角,角FCG为锐角,故大边对大角,得FC大于FG。

  4. Similarly we can prove that neither is any other straight line except FC; therefore FC is perpendicular to DE.

    但FC等于FB,故FB也大于FG,矛盾。因此FC垂直于DE。