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数学 / 几何原本 / Proposition VI.12

第6卷命题 12 · 求三条已知线段的第四比例项

elem.6.12

给定三条线段A、B、C,求作一条线段X,使得A比B等于C比X。

A B C D E F G H
fig-1

求三条已知量 A、B、C 的第四比例项(DE、EF、DG 分别表示 A、B、C):在两条相交线上分别截取已知段,过 F 作平行于 EG 的直线交另一线于 H,则 GH 为所求第四比例项。

线

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分步证明Step-by-step proof
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  1. Let A, B, C be the three given straight lines; thus it is required to find a fourth proportional to A, B, C.

    作任意角∠EDF,在DE上截取DG等于A,GE等于B,在DF上截取DH等于C。

  2. Let two straight lines DE, DF be set out containing any angle EDF; let DG be made equal to A, GE equal to B, and further DH equal to C; let GH be joined, and let EF be drawn through E parallel to it.

    连接GH,过E作EF平行于GH(I.31)。

  3. [I. 31] Since, then, GH has been drawn parallel to EF, one of the sides of the triangle DEF, therefore, as DG is to GE, so is DH to HF.

    因为GH平行于三角形DEF的一边EF,所以DG比GE等于DH比HF(VI.2)。

  4. [VI. 2] But DG is equal to A, GE to B, and DH to C; therefore, as A is to B, so is C to HF.

    由于DG等于A,GE等于B,DH等于C,因此A比B等于C比HF,即HF为所求第四比例项。